Class 10 | NCERT Solution | Chapter: 10

Here are clear answers to your questions from the chapter

🌈 The Human Eye and the Colourful World — Class 10 NCERT, CBSE Board:





✅ Q1.



The human eye can focus on objects at different distances by adjusting the focal length of the eye lens. This is due to —

🎯 (b) accommodation.





✅ Q2.



The human eye forms the image of an object at its —

🎯 (d) retina.





✅ Q3.



The least distance of distinct vision for a young adult with normal vision is about —

🎯 (c) 25 cm.





✅ Q4.



The change in focal length of an eye lens is caused by the action of the —

🎯 (c) ciliary muscles.





✅ Q5.



A person needs a lens of power –5.5 D for distant vision and +1.5 D for near vision. What are the focal lengths of these lenses?


  • Formula: f = \frac{100}{P} (in cm)
  • For distant vision: P = -5.5 ⇒ f = \frac{100}{-5.5} ≈ -18.18 cm = –0.1818 m
  • For near vision: P = +1.5 ⇒ f = \frac{100}{1.5} ≈ 66.7 cm = 0.667 m






✅ Q6.



The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required?


  • To correct myopia, we use a concave lens.
  • u = -\infty, v = -80 cm.
  • \frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{-80} - 0 = -\frac{1}{80} m.
  • f ≈ -0.8 m ⇒ P = \frac{100}{-80} = -1.25 D.
    🎯 Lens: Concave, power ≈ –1.25 D






✅ Q7.



Make a diagram to show how hypermetropia is corrected.

📐 A convex lens is used to converge light rays so they focus properly on the retina.



Calculation:



  • Near point of hypermetropic eye = 1 m
  • Near point of normal eye = 25 cm.
  • u = –25 cm, v = –100 cm.
  • \frac{1}{f} = \frac{1}{v} – \frac{1}{u} = \frac{1}{–100} – \frac{1}{–25} = –0.01 + 0.04 = 0.03 cm^{-1}
  • f ≈ 33.3 cm ⇒ P ≈ +3 D
    🎯 Lens: Convex, power ≈ +3 D






✅ Q8.



Why can’t a normal eye see objects closer than 25 cm?


  • Because the ciliary muscles cannot make the eye lens sufficiently thick beyond a certain limit to focus very near objects.






✅ Q9.



What happens to the image distance in the eye when we increase the distance of an object?


  • The image distance in the eye remains fixed (equal to the distance between lens and retina), and the focal length of the eye lens is adjusted by the ciliary muscles.






✅ Q10.



Why do stars twinkle?


  • Due to the refraction of starlight by the atmosphere which is constantly changing (atmospheric turbulence), making the star’s position and brightness appear to fluctuate.






✅ Q11.



Why don’t planets twinkle?


  • Planets appear larger (finite disc) compared to point-sized stars, so the variations in atmospheric refraction average out and don’t produce noticeable twinkling.






✅ Q12.



Why does the sky appear dark instead of blue to an astronaut?


  • In space, there is no atmosphere to scatter sunlight, so the sky appears black instead of blue.





📖 If you’d also like, I can prepare:

✨ Ray diagrams (for hypermetropia & myopia)

✨ A colorful HTML page

✨ Or a printable PDF of all these answers neatly formatted.


Would you like that? Let me know!